Question
Find the following products:
$\left(y^2-4\right)\left(y^2-3\right)$
$\left(y^2-4\right)\left(y^2-3\right)$
✓
Answer
Here, we will use the identity $(x-a)(x-b)=x^2-(a+b) x+a b$.
$\left(y^2-4\right)\left(y^2-3\right)$
$=(y 2)^2-(4+3)\left(y^2\right)+4 \times 3$
$=y^4-7 y^2+12$
$\left(y^2-4\right)\left(y^2-3\right)$
$=(y 2)^2-(4+3)\left(y^2\right)+4 \times 3$
$=y^4-7 y^2+12$
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