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Trigonometric Functions — Maths STD 12 Science — Question

Maharashtra BoardEnglish MediumSTD 12 ScienceMathsTrigonometric Functions2 Marks
Question
Find the general solution of : $\sin \theta=\frac{\sqrt{3}}{2}$
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Answer

We have $\sin \theta=\frac{\sqrt{3}}{2}$$
\therefore \quad \sin \theta=\sin \frac{\pi}{3}
$
The general solution of $\sin \theta=\sin \alpha$ is $\theta=n \pi+(-1)^n \alpha$, where $n \in Z$.
$\therefore \quad$ The general solution of $\sin \theta=\sin \frac{\pi}{3}$ is $\theta=n \pi+(-1)^n \frac{\pi}{3}$, where $n \in Z$.
$\therefore \quad$ The general solution of $\sin \theta=\frac{\sqrt{3}}{2}$ is $\theta=n \pi+(-1)^n \frac{\pi}{3}$, where $n \in Z$.

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