Maharashtra BoardEnglish MediumSTD 12 ScienceMathsTrigonometric Functions1 Mark
Question
Find the general solution of : $\tan ^2 \theta=1$
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Answer
We have $\tan ^2 \theta=1$ $\therefore \quad \tan ^2 \theta=\tan ^2 \frac{\pi}{4}$ The general solution of $\tan ^2 \theta=\alpha$ is $\theta=n \pi \pm \alpha$, where $n \in Z$. $\therefore \quad$ The general solution of $\tan ^2 \theta=\tan ^2 \frac{\pi}{4}$ is $\theta= n \pi \pm \frac{\pi}{4}$, where $n \in Z$. $\therefore \quad$ The general solution of $\tan ^2 \theta=1$ is $\theta=n \pi \pm \frac{\pi}{4}$, where $n \in Z$.
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