Question
Find the general solution of :$\tan \theta=\sqrt{3}$

Answer

$\tan \theta=\sqrt{3}$
$
\therefore \quad \tan \theta=\tan \frac{\pi}{3}
$
The general solution of $\tan \theta=\tan \alpha$ is $\theta= n \pi+\alpha$, where $n \in Z$.
$\therefore \quad$ The general solution of $\tan \theta=\tan \frac{\pi}{3}$ is $\theta= n \pi+\frac{\pi}{3}$ where $n \in Z$.
$\therefore \quad$ The general solution of $\tan \theta=\sqrt{3}$ is $\theta= n \pi+\frac{\pi}{3}$, where $n \in Z$.

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