Find the general solutions of the following equations: =2 - Vidyadip

Question

Find the general solutions of the following equations: $\sec\text{x}=\sqrt{2}$

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Answer

we have, $\sec\text{x}=\sqrt{2}$ $\Rightarrow\frac{1}{\cos\theta}=\sqrt{2}$ $\Rightarrow\cos\theta=\frac{1}{\sqrt{2}}\Rightarrow\cos\theta=\cos\frac{\pi}{4}$ $\Rightarrow\theta=2\text{n}\pi\pm\frac{\pi}{4},\text{n}\in\text{z}$

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