Question
Find the general solutions of the following equations:
$\sqrt{3}\sec\text{x}=2$

Answer

we have,
$\sqrt{3}\sec\text{x}=2$
$\Rightarrow\frac{1}{\cos\theta}=\frac{2}{\sqrt{3}}$
$\Rightarrow\cos\theta=\frac{\sqrt{3}}{2}$
$\Rightarrow\cos\theta=\cos\Big(\frac{\pi}{6}\Big)$
$\Rightarrow\theta=2\text{n}\pi\pm\frac{\pi}{6},\text{n}\in\text{z}$

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