Question
Find the general solutions of the following equations:
$\tan\text{px}=\cot\text{qx}$

Answer

We have,
$\tan\text{px}=\cot\text{qx}$
$\Rightarrow\tan\text{px}=\tan\Big(\frac{\pi}{2}-\text{qx}\Big)$
$\Rightarrow\text{px}=\text{nx}\pm\Big(\frac{\pi}{2}-\text{qx}\Big),\text{n}\in\text{z}$
$\Rightarrow\text{(p+q)}\text{x}=\text{n}\pi+\frac{\pi}{2},\text{n}\in\text{z}$
$\Rightarrow\text{(p+q)}\text{x}=\text{(2n+1)}\frac{\pi}{2},\text{n}\in\text{z}$
$\Rightarrow\text{x}=\frac{\text{(2n+1)}}{\text{(p+q)}}\frac{\pi}{2},\text{n}\in\text{z}$

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