Question
Find the $HCF$ of the numbers in the following using the prime factorization method:$106, 159, 371$
✓
Answer
The given numbers are $106, 159$ and $371$.We have:
$\begin{array}{c|c}2&106\\\hline53&53\\\hline&1\end{array}$
$\begin{array}{c|c}3&159\\\hline53&53\\\hline&1\end{array}$
$\begin{array}{c|c}7&371\\\hline53&53\\\hline&1\end{array}$
Now, $106=2\times53$
$159=3\times53$
$371=7\times53$
$\therefore HCF =53$
$\begin{array}{c|c}2&106\\\hline53&53\\\hline&1\end{array}$
$\begin{array}{c|c}3&159\\\hline53&53\\\hline&1\end{array}$
$\begin{array}{c|c}7&371\\\hline53&53\\\hline&1\end{array}$
Now, $106=2\times53$
$159=3\times53$
$371=7\times53$
$\therefore HCF =53$
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