Question
Find the HCF of the numbers in the following using the prime factorization method:272, 425

Answer

The given numbers are 272 and 425.We have:
$\begin{array}{c|c}2&272\\\hline2&136\\\hline2&68\\\hline2&34\\\hline17&17\\\hline&1\end{array}$
$\begin{array}{c|c}5&425\\\hline5&85\\\hline17&17\\\hline&1\end{array}$
Now, $272=2\times2\times2\times2\times17$
$425=5\times5\times17$
$\therefore$ The required HCF is 17.

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