Gujarat BoardEnglish MediumSTD 12 ScienceMathsIntegrals1 Mark
Question
Find the integral: $\int \frac{1-\sin x}{\cos ^{2} x} d x$
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Answer
We have $\int \frac{1-\sin x}{\cos ^{2} x} d x=\int \frac{1}{\cos ^{2} x} d x-\int \frac{\sin x}{\cos ^{2} x} d x$ = $\int \sec ^{2} x d x-\int \tan x \sec x d x$ = tan x - sec x + C
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