Question
Find the integral: $\int \frac{d x}{x^{2}-16}$

Answer

We have $\int \frac{d x}{x^{2}-16}=\int \frac{d x}{x^{2}-4^{2}}=\frac{1}{8} \log \left|\frac{x-4}{x+4}\right|+C$$~~~(Using \int \frac{d x}{x^{2}-a^{2}}=\frac{1}{2 a} \log \left|\frac{x-a}{x+a}\right|+C)$

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