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Integrals — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMathsIntegrals2 Marks
Question
Find the integral: $\int \frac{2-3 \sin x}{\cos ^{2} x} d x$ 
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Answer

$\int \frac{2-3 \sin x}{\cos ^{2} x} d x$ 
= $\int\left(\frac{2}{\cos ^{2} x}-\frac{3 \sin x}{\cos ^{2} x}\right) d x$ 
= $\int 2 \sec ^{2} x d x-3 \int \tan x \sec x d x$ 
= 2tan x - 3sec x + C

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