Find the integral: (2 x-3 x+e^ x ) d x

Question

Find the integral: $\int\left(2 x-3 \cos x+e^{x}\right) d x$

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Answer

$\int\left(2 x-3 cos x+e^{x}\right) d x$
= $2 \int x d x-3 \int \cos x d x+\int e^{x} d x$
= $\frac{2 x^{2}}{2}-3(\sin x)+e^{x}+C$
= $x^{2}-3 \sin x+e^{x}+C$

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