Question
Find the integral: $\int\left(4 e^{3 x}+1\right) d x$

Answer

$\int\left(4 e^{3 x}+1\right) d x=4 \int e^{3 x} d x+\int 1 d x$
= $4\left(\frac{\mathrm{e}^{3 \mathrm{x}}}{3}\right)+\mathrm{x}+\mathrm{C}$ 
= $\frac{4}{3} e^{3 x}+x+C$ 

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