Question
Find the integral of the function $\frac{{{{\sin }^2}x}}{{1 + \cos x}}$
$= \int {\frac{{1 - {{\cos }^2}x}}{{1 + \cos x}}} dx$
$= \int {\frac{{\left( {1 - \cos x} \right)\left( {1 + \cos x} \right)}}{{1 + \cos x}}} dx$
$= \int {\left( {1 - \cos x} \right)} dx$
$= \int {1dx - \int {\cos x} } dx$
= x - sin x + c
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.