Question
Find the integrals of the functions in Exercises:
$\frac{\cos2\text{x}}{(\cos\text{x}+\sin\text{x})^2}$

Answer

$\frac{\cos2\text{x}}{(\cos\text{x}+\sin\text{x})^2}=\frac{\cos2\text{x}}{\cos^2\text{x}+\sin^2\text{x}+2\sin\text{x}\cos\text{x}}=\frac{\cos2\text{x}}{1+\sin2\text{x}}$
$\therefore\int\frac{\cos2\text{x}}{(\cos\text{x}+\sin\text{x})^2}\text{ dx}=\int\frac{\cos2\text{x}}{(1+\sin2\text{x})}\text{dx}$
$\text{Let }1+\sin2\text{x}=\text{t}$
$\Rightarrow2\cos2\text{x}\text{ dx}=\text{dt}$
$\therefore\int\frac{\cos2\text{x}}{(\cos\text{x}+\sin\text{x})^2}\text{dx}=\frac{1}{2}\int\frac{1}{\text{t}}\text{dt}$
$=\frac{1}{2}\log|\text{t}|+\text{C}$
$=\frac{1}{2}\log|1+\sin2\text{x}|+\text{C} $
$=\frac{1}{2}\log|(\sin\text{x}+\cos\text{x})^2|+\text{C} $
$=\log|\sin\text{x}+\cos\text{x}|+\text{C}$

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