Question
Find the interval in function 6 - 9x - x2 is increasing or decreasing.

Answer

It is given that function f(x) = 6 - 9x - x2
f'(x) = -9 - 2x
If f'(x) = 0, 
$\Rightarrow x=\frac{-9}{2}$ 
So, the point x = $\frac{-9}{2}$ divides the real line two disjoint intervals, $\left(-\infty, \frac{-9}{2}\right)$ and $\left(\frac{-9}{2}, \infty\right)$ 
So, in interval $\left(-\infty, \frac{-9}{2}\right)$ 
f'(x) = -9 - 2x > 0
Therefore, the given function 'f' is strictly increasing for x < $\frac{-9}{2}$.
And in interval $\left(\frac{-9}{2}, \infty\right)$ 
f'(x) = -9 - 2x < 0
Therefore, the given function 'f' is strictly decreasing for $x>\frac{-9}{2}$ 
Thus, f is strictly decreasing for $x>\frac{-9}{2}$ 

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