Application of Derivatives — Maths STD 12 Science — Question
Gujarat BoardEnglish MediumSTD 12 ScienceMathsApplication of Derivatives1 Mark
Question
Find the interval in function 6 - 9x - x2 is increasing or decreasing.
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Answer
It is given that function f(x) = 6 - 9x - x2 f'(x) = -9 - 2x If f'(x) = 0, $\Rightarrow x=\frac{-9}{2}$ So, the point x = $\frac{-9}{2}$ divides the real line two disjoint intervals, $\left(-\infty, \frac{-9}{2}\right)$ and $\left(\frac{-9}{2}, \infty\right)$ So, in interval $\left(-\infty, \frac{-9}{2}\right)$ f'(x) = -9 - 2x > 0 Therefore, the given function 'f' is strictly increasing for x < $\frac{-9}{2}$. And in interval $\left(\frac{-9}{2}, \infty\right)$ f'(x) = -9 - 2x < 0 Therefore, the given function 'f' is strictly decreasing for $x>\frac{-9}{2}$ Thus, f is strictly decreasing for $x>\frac{-9}{2}$
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