Question
Find the interval of the function that is strictly increasing or decreasing: (x + 1)3 (x - 3)

Answer

$f(x) = {(x + 1)^3}{(x - 3)^3}$
$f'(x) = {(x + 1)^3}.3{(x - 3)^2} + {(x - 3)^3}.3{(x + 1)^2}$
$ = 3{(x + 1)^2}{(x - 3)^2}[x + 1 + x - 3]$
$ = 3{(x + 1)^2}{(x - 3)^2}[2x - 2]$
$ = 6{(x + 1)^2}{(x - 3)^2}(x - 1)$
Put f'(x) = 0
x = -1, 3, 1

int Sign of f’(x) Result
$( - \infty , - 1)$ -ve Decrease
(-1, 1) -ve Decrease
(1, 3) +ve Increase
$(3,\infty )$ +ve Increase

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