Question
Find the intervals in which $\text{f(x)} = \sin 3x - \cos 3x, 0 < x < \pi.$ is strictly increasing or strictly decreasing.

Answer

$\text{f(x)} = \sin \text{3x} - \cos \text{3x}, 0 < \text{x} < \pi.$
$\text{f'(x)} = 3\cos3\text{x} + 3\sin\text{3x}$
$\text{f'(x)} = 0 \Rightarrow \tan 3\text{x} = -1$
$\Rightarrow\text{x} = \frac{\text{n}\pi}{3} + \frac{\pi}{4}, \text{n}\in\text{Z}$
$\Rightarrow\text{x} = \frac{\pi}{4}, \frac{7\pi}{12}, \frac{11\pi}{12}$
$\text{Intervals are:} \bigg(0,\frac{\pi}{4}\bigg), \bigg(\frac{\pi}{4},\frac{7\pi}{12}\bigg), \bigg(\frac{7\pi}{12}, \frac{11\pi}{12}\bigg),\bigg(\frac{11\pi}{12}, \pi\bigg)$
$\text{f(x) is strictly increasing in} \bigg(0, \frac{\pi}{4}\bigg)\cup\bigg(\frac{7\pi}{12},\frac{11\pi}{12}\bigg)$
$\text{and strictly decreasing in} \bigg(\frac{\pi}{4},\frac{7\pi}{12}\bigg)\cup\bigg(\frac{11\pi}{12},\pi\bigg)$

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