Question
Find the intervals in which the following functions are increasing or decreasing.
f(x) = 2x3 - 15x2 + 36x + 1

Answer

f(x) = 2x3 - 15x2 + 36x + 1
f'(x) = 6x2 - 30x + 36
= 6(x2 - 5x + 6)
= 6(x - 2)(x - 3)
For f(x) to be increasing, we must have
f'(x) > 0
⇒ 6(x - 2)(x - 3) > 0
⇒ (x - 2)(x - 3) > 0
[Since, 6 > 0, 6 (x - 2)(x - 3) > 0 ⇒ (x - 2)(x - 3) > 0]
⇒ x < 2 or x > 3
$\Rightarrow\text{x}\in(-\infty,2)\cup(3,\infty)$
So, f(x) is increasing on $\text{x}\in(-\infty,2)\cup(3,\infty).$
For f(x) to be decreasing, we must have,
f'(x) < 0
⇒ 6(x - 2)(x - 3) < 0
⇒ (x - 2)(x - 3) < 0
[Since, 6 > 0, 6 (x - 2)(x - 3) < 0 ⇒ (x - 2)(x - 3) < 0]
⇒ 2 < x < 3
$\Rightarrow\text{x}\in(2,3)$
So, f(x) is decreasing on $\text{x}\in(2,3).$

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