Question
Find the intervals in which the following functions are increasing or decreasing.
$f(x) = 2x^3 - 15x^2 + 36x + 1$

Answer

$f(x) = 2x^3 - 15x^2 + 36x + 1$
$f'(x) = 6x^2 - 30x + 36$
$= 6(x^2 - 5x + 6)$
$= 6(x - 2)(x - 3)$
For $f(x)$ to be increasing, we must have
$f'(x) > 0$
$\Rightarrow 6(x - 2)(x - 3) > 0$
$\Rightarrow (x - 2)(x - 3) > 0$
$[$Since, $6 > 0, 6 (x - 2)(x - 3) > 0 \Rightarrow (x - 2)(x - 3) > 0]$
$\Rightarrow x < 2$ or $x > 3$
$\Rightarrow\text{x}\in(-\infty,2)\cup(3,\infty)$
So, $f(x)$ is increasing on $\text{x}\in(-\infty,2)\cup(3,\infty).$
For $f(x)$ to be decreasing, we must have,
$f'(x) < 0$
$\Rightarrow 6(x - 2)(x - 3) < 0$
$\Rightarrow (x - 2)(x - 3) < 0$
$[$Since, $6 > 0, 6 (x - 2)(x - 3) < 0 \Rightarrow (x - 2)(x - 3) < 0]$
$\Rightarrow 2 < x < 3$
$\Rightarrow\text{x}\in(2,3)$
So, $f(x)$ is decreasing on $\text{x}\in(2,3).$

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