Question
Find the intervals in which the following functions are increasing or decreasing.
$f(x) = (x - 1)(x - 2)^2$

Answer

$f(x) = (x - 1)(x - 2)^2$
$= (x - 1)(x^2 - 4x + 4)$
$= x^3 - 5x^2+ 8x - 4$
$f'(x) = 3x^2 - 10x + 8$
$= 3x^2 - 6x - 4x + 8$
$= (x - 2)(3x - 4)$
For f(x) to be increasing, we must have
$f'(x) > 0$
$\Rightarrow (x - 2)(3x - 4) > 0$
$\Rightarrow\text{x}<\frac{4}{3}\text{ or }\text{x}>2$
$\Rightarrow\text{x}\in\Big(-\infty,-\frac{4}{3}\Big)\cup(2,\infty)$
So, f(x) is increasing on $\text{x}\in\Big(-\infty,-\frac{4}{3}\Big)\cup(2,\infty).$
For f(x) to be decreasing, we must have,
$f'(x) < 0$
$\Rightarrow (x - 2)(3x - 4) < 0$
$\Rightarrow\frac{4}{3}<\text{x}<2$
$\Rightarrow\text{x}\in\Big(\frac{4}{3},2\Big)$
So, f(x) is decreasing on $\text{x}\in\Big(\frac{4}{3},2\Big).$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If $e^y= y^x,$ prove that $\frac{\text{dy}}{\text{dx}}=\frac{(\log\text{y})^2}{\log\text{y}-1}$
Solve the following differential equations:$(1+\text{x})(1+\text{y}^2)\text{dx}+(1+\text{y})(1+\text{x}^2)\text{dy}=0$
Evaluate the following integrals:$\int\frac{2\text{x}}{2+\text{x}-\text{x}^2}\text{ dx}$
Determine whether the following pair of lines intersect or not:
$\frac{\text{x}-1}{2}=\frac{\text{y}+1}{3}=\text{z}$ and $\frac{\text{x}+1}{5}=\frac{\text{y}-2}{1};\text{z}=2$
Solve the following differential equation:
$(\text{x}+\tan\text{y})\text{dy}=\sin2\text{y dx}$
Evaluate the following integrals:$\int^\limits2_{-2}|2\text{x}+3|\text{dx}$
Solve the following differential equations:$\text{xy}\frac{\text{dy}}{\text{dx}}=\text{y}+2,\text{y}(2)=0$
Evaluate the following integrals:$\int\limits^{\frac{\pi}{3}}_\frac{\pi}{6}\frac{1}{1+\cot^{\frac{3}{2}}\text{x}}\text{ dx}$
A diet for a sick person must contain at least $4000$ units of vitamins, $50$ units of minerals and $1400$ of calories. Two foods $A$ and $B$, are available at a cost of Rs $4$ and Rs $3$ per unit respectively. If one unit of A contains $200$ units of vitamin, $1$ unit of mineral and $40$ calories and one unit of food $B$ contains $100$ units of vitamin, $2$ units of minerals and $40$ calories, find what combination of foods should be used to have the least cost?
Differentiate the following functions with respect to x:
$\tan^{-1}\Big(\frac{\text{a}+\text{b}\tan\text{x}}{\text{b}-\text{a}\tan\text{x}}\Big)$