Question
Find the intervals in which the function f given by $f(x) = x^2 – 4x + 6$ is
  1. increasing
  2. decreasing

Answer

We have
$f (x) = x^2 – 4x + 6$
or $f ′(x) = 2x – 4$
Therefore, $f ′(x) = 0$ gives $x = 2$.
Now the point $x = 2$ divides the real line into two disjoint intervals namely, $(– \infty, 2)$ and $(2, \infty).$

In the interval $(– \infty, 2), f ′(x) = 2x – 4 < 0.$
And in interval $(2, \infty ),  f^\prime(x)=2x-4>0$
$\therefore (i) f $ is increasing in $(2, \infty$)
and $(ii)$ f is decreasing in $(–\infty, 2)$

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