Question
Find the $LCM$ and $HCF$ of the following integer by applying the prime factorisation method.
$24, 15$ and $36$
$24, 15$ and $36$
✓
Answer
Let us first find the factors of $24, 15$ and $36$.
$24 = 2^3 \times 3$
$15 = 3 \times 5$
$36 = 2^2 \times 3^2$
$L.C.M$ of $24, 15$ and $36 = 2^3 \times 3^2 \times 5$
$L.C.M$ of $24, 15$ and $36 = 360$
$H.C.F$ of $24, 15$ and $36 = 3$
$24 = 2^3 \times 3$
$15 = 3 \times 5$
$36 = 2^2 \times 3^2$
$L.C.M$ of $24, 15$ and $36 = 2^3 \times 3^2 \times 5$
$L.C.M$ of $24, 15$ and $36 = 360$
$H.C.F$ of $24, 15$ and $36 = 3$
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