Question
Find the LCM and HCF of the following integer by applying the prime factorisation method.
$40, 36$ and $126$
$40, 36$ and $126$
✓
Answer
Let us first find the factors of $40, 36$ and $126$
$40 = 2^3 \times 5$
$36 = 2^2 \times 3^2$
$126 = 2 \times 3^2 \times 7$
$L.C.M$ of $40, 36$ and $126 = 2^3 \times 3^2 \times 5 \times 7$
$L.C.M$ of $40, 36$ and $126 = 2520$
$H.C.F$ of $40, 36$ and $126 = 2$
$40 = 2^3 \times 5$
$36 = 2^2 \times 3^2$
$126 = 2 \times 3^2 \times 7$
$L.C.M$ of $40, 36$ and $126 = 2^3 \times 3^2 \times 5 \times 7$
$L.C.M$ of $40, 36$ and $126 = 2520$
$H.C.F$ of $40, 36$ and $126 = 2$
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