Question
Find the least number of three digits which is perfect square.
✓
Answer
Let us make a list of the squares starting from $1$.
$ 1^2=1 $
$ 2^2=4 $
$ 3^2=9 $
$ 4^2=16 $
$ 5^2=25 $
$ 6^2=36 $
$ 7^2=49 $
$ 8^2=64 $
$ 9^2=81 $
$ 10^2=100 $
The square of $10$ has three digits.
Hence, the least three-digit perfect square is $100$
$ 1^2=1 $
$ 2^2=4 $
$ 3^2=9 $
$ 4^2=16 $
$ 5^2=25 $
$ 6^2=36 $
$ 7^2=49 $
$ 8^2=64 $
$ 9^2=81 $
$ 10^2=100 $
The square of $10$ has three digits.
Hence, the least three-digit perfect square is $100$
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