Application of Derivatives — MATHS STD 12 Science — Question
Rajasthan BoardEnglish MediumSTD 12 ScienceMATHSApplication of Derivatives2 Marks
Question
Find the maximum and minimum value, f(x) = |x + 2| - 1
✓
Answer
It is given that f(x) = |x + 2| - 1 Now, we can see that |x + 2| $\ge$ 0 for every x $\in$ R $\Rightarrow f(x)=|x+2|-1 \geq-1$ for every x $\in$ R Clearly, the minimum value of f is attained when |x + 2| = 0 i.e, |x + 2| = 0 $\Rightarrow$ x = -2 Then, Minimum value of f = f(-2) = |-2 + 2| - 1 = -1 Therefore, function f does not have a maximum value.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.