Application of Derivatives — MATHS STD 12 Science — Question
Rajasthan BoardEnglish MediumSTD 12 ScienceMATHSApplication of Derivatives2 Marks
Question
Find the maximum and minimum value, g(x) = -|x + 1| + 3
✓
Answer
It is given that g(x) = -|x + 1| + 3 Now, we can see that -|x + 1| $\le$ 0 for every x $\in$ R $\Rightarrow g(x)=-|x+1|+3 \leq 3$ for every x $\in$ R The maximum value of f is attained when |x + 1| = 0 |x + 1| = 0 $\Rightarrow x=-1$ Then, Maximum value of g = g(-1) = -|-1 + 1| + 3 = 3 Therefore, function f does not have a minimum value.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.