MCQ
Find the maximum number of atoms that lie in the same plane in $PCl_5$ molecule :
- A$3$
- B$5$
- ✓$4$
- D$2$
Hence, Maximum 4 atoms (one P and 3 Cl) are possible in same plane.
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$C$ $ (graphite) $ $ + {O_2}(g) \to C{O_2}(g);\,\Delta H = - 393.5$
If the graphite is made of diamond then the above figure is $\Delta H$.......$kJ$
$(A)$ Homolytic bond cleavage
$(B)$ Heterolytic bond cleavage
$(C)$ Free radical formation
$(D)$ Primary free radical
$(E)$ Secondary free radical
Choose the correct answer from the options given below: