Question
Find the mean of the following frequency distribution using a suitable method.
Class
$20-30$
$30-40$
$40-50$
$50-60$
$60-70$
Frequency
$25$
$40$
$42$
$33$
$10$

Answer

Class interval
Frequency $f_i$
Mid-value $x_i$
$\text{u}_\text{i}=\frac{\text{x}_\text{i}-\text{A}}{\text{h}}=\frac{\text{x}_\text{i}-203.5}{1}$
$f_i \times u_i$
$20-30$
$25$ $25$ $-20$ $-500$
$30-40$
$40$
$35$ $-10$ $-400$
$40-50$
$42$
$45 = A$ $0$ $0$
$50-60$
$33$ $55$ $10$ $330$
$60-70$
$10$ $65$ $20$ $200$
 
$\sum\text{f}_\text{i}=150$
 
 
$\sum\text{f}_\text{i}\text{u}_\text{i}=-370$
Thus, $\text{A}=45,\ \sum\text{f}_\text{i}=150$ and $\sum\text{f}_\text{i}\text{u}_\text{i}=-370$
Mean $=\text{A}+\Big\{\text{h}\times\frac{\sum\text{f}_\text{i}\text{u}_\text{i}}{\sum\text{f}_\text{i}}\Big\}$
$45+\frac{(-370)}{150}$
$=45-2.47$
$=42.53$

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