Find the minimum value of $m$ that should placed on $20\, kg$, so that system remain at rest ........ $kg$
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$10 \mathrm{g}=\mu(\mathrm{m}+20) \mathrm{g}$
$\Rightarrow 10=0.25(\mathrm{m}+20) \Rightarrow \mathrm{m}=20 \mathrm{kg}$
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