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COMPLEX NUMBERS AND QUADRATIC EQUATIONS — MATHS STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceMATHSCOMPLEX NUMBERS AND QUADRATIC EQUATIONS2 Marks
Question
Find the multiplicative inverse of the complex numbers 4 - 3i
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Answer

M.I. of (4 - 3i)$ = \frac{1}{{4 - 3i}} = \frac{1}{{4 - 3i}} \times \frac{{4 + 3i}}{{4 + 3i}} = \frac{{4 + 3i}}{{{{(4)}^2} - {{(3i)}^2}}}$
$ = \frac{{4 + 3i}}{{16 - 9{i^2}}} = \frac{{4 + 3i}}{{16 + 9}} = \frac{1}{{25}}(4 + 3i)$

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