Question
Find the odd one out.

Answer

  1. Sodium
Explanation:
In this, sodium is the odd one out because, sodium, being an alkali metal, is photosensitive while the others are not photosensitive materials. Sodium metal emits electrons even when ordinary light falls on it. Therefore, it is known as a photosensitive material.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

What happens to the magnetic field at the centre of a circular current carrying coil if we double the radius of the coil keeping the current unchanged?
When the resistance of $9\Omega$ is connected at the ends of a battery, its potential difference decreases from $40$ volt to $30$ volt. The internal resistance of the battery is
A solenoid of inductance L carrying a certain current is linked with a total magnetic flux $\phi$. Now it is connected to a condenser with which it shares half of its initial energy. The total flux now linked with the solenoid is:
Which of the following did Bohr use to explain his theory?
A player with $3 m$ long iron rod runs towards east with a speed of $30 \ km/hr.$ Horizontal component of earth's magnetic field is $4\times 10^{-5} \mathrm{wb} / \mathrm{m}^2$.. If he is running with rod in horizontal and vertical positions, then the potential difference induced between the two ends of the rod in two cases will be
+ 2C and +6C two charges are repelling each other with a force of 12N.  If each charge is given  -2C of charge, then the value of the force will be(a) 4N  (Attractive)(b) 4N  (Repulsive)(c) 8N (Repulsive)(d) Zero
       
Suppose the medium in the previous question is water. Select the correct option$(s)$ from the list given in that question.
Let p and E denote the linear momentum and the energy of a photon. For another photon of smaller wavelength (in same medium):
A bar $-$ magnet of the pole-strength $2 Amp - m$ is kept in a magnetic field of induction $4 \times 10^{-5} Wb / m ^2$ such that the axis of the magnet makes an angle $30^{\circ}$ with the direction of the field. If the couple acting on the magnet is found to be $80 \times 10^{-7} Nm$, then the distance between the poles of the magnet is:
$ABC$ is a right angled triangle in which $AB = 3 \ cm$ and $BC = 4 \ cm$. And $\angle ABC = \pi/2.$ The three charges $+15, +12$ and $-20\ e.s.u.$ are placed respectively on $A, B$ and $C.$ The force acting on $B$  is