Question
Find the perimeter of a rectangle in which: length $= 8m$ 5dm and breadth $= 6m 8dm$
✓
Answer
Length of rectangle $(l) = 8m 5dm = 8.5m$ And
breadth $(b) = 6m 8dm = 6.8m$
$\therefore$ Perimeter $= 2(l + b) = 2(8.5 + 6.8)m = 2 \times 15.3m = 30.6m = 30m 6dm$ or $306dm$
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