Question
Find the perimeter of a rectangle whose area is $500cm^2$ and breadth is $20\ cm.$

Answer

Area $= 500\ cm^2$
Breadth $= 20\ cm$
Area of rectangle $=$ (Length $\times $ Breadth)
Therefore Length $=\frac{\text{Area}}{\text{Breadth}}$
$=\frac{500}{20}=25\text{cm}$
Perimeter of a rectangle $= 2$(Length $+$ Breadth)
$= 2(25 + 20)cm$
$= 2 \times 45\ cm$
$= 90\ cm$

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