Question
Find the perimeter of a rectangle whose area is $500\ cm^2$ and breadth is $20\ cm.$
✓
Answer
Area $= 500\ cm^2$
Breadth $= 20\ cm$
Area of rectangle = (Length × Breadth)
Therefore Length $=\frac{\text{Area}}{\text{Breadth}}$
$=\frac{500}{20}=25\text{cm}$
Perimeter of a rectangle = 2(Length + Breadth)
$= 2(25 + 20)\ cm$
$= 2 \times 45\ cm$
$= 90\ cm$
Breadth $= 20\ cm$
Area of rectangle = (Length × Breadth)
Therefore Length $=\frac{\text{Area}}{\text{Breadth}}$
$=\frac{500}{20}=25\text{cm}$
Perimeter of a rectangle = 2(Length + Breadth)
$= 2(25 + 20)\ cm$
$= 2 \times 45\ cm$
$= 90\ cm$
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