Question
Find the perimeter of a rectangle whose area is $600cm^2$ and breadth is $25\ cm.$
✓
Answer
Here, the length of the rectangle $=\frac{600}{25} = 24\ cm$
So, the perimeter of the rectangle $= 2(25 + 24) = 2 \times 49 = 98\ cm (15)$
Fing the area of a square whose diagonal is $5\sqrt{2}\text{cm}$
We, know, Area of a square $=\Big\{\frac{1}{2}\times (\text{diagonal})^2\Big\}$
$\therefore$ Area $=\Big\{\frac{1}{2}\times (5\sqrt{2})^2\Big\}$
$=\frac{1}{2}\times 50$
$25\text{cm}^2$
So, the perimeter of the rectangle $= 2(25 + 24) = 2 \times 49 = 98\ cm (15)$
Fing the area of a square whose diagonal is $5\sqrt{2}\text{cm}$
We, know, Area of a square $=\Big\{\frac{1}{2}\times (\text{diagonal})^2\Big\}$
$\therefore$ Area $=\Big\{\frac{1}{2}\times (5\sqrt{2})^2\Big\}$
$=\frac{1}{2}\times 50$
$25\text{cm}^2$
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