Question
Find the perimeter of a semicircular protractor whose diameter is 14 cm.
✓
Answer
Diameter of a semicircular protractor = 14cm
⇒ Radius of a semicircular protractor = r = 7cm
$\therefore$ Perimeter of a semicircular protractor $=(\pi\text{r}+2\text{r})$
$= \text{r} (\pi+2)$
$=7\Big(\frac{22}{7}+2\Big)\text{cm}$
$=7\Big(\frac{22+14}{7}\Big)\text{cm}$
$=7\times\frac{36}{7}$
$=36\text{cm}$
⇒ Radius of a semicircular protractor = r = 7cm
$\therefore$ Perimeter of a semicircular protractor $=(\pi\text{r}+2\text{r})$
$= \text{r} (\pi+2)$
$=7\Big(\frac{22}{7}+2\Big)\text{cm}$
$=7\Big(\frac{22+14}{7}\Big)\text{cm}$
$=7\times\frac{36}{7}$
$=36\text{cm}$
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