Find the potential difference $V_a -V_b$ between the points $a$ and $b$ shown in each part of the figure.
Diffcult
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$(x-12) 2+(x-0) \cdot \frac{4}{3}+(x-0) .4=0$
$2 x-24+\frac{4 x}{3}+4 x=0$
$6 x+\frac{4 x}{3}=24$
$x=\frac{36}{11} \,V$
$(Y-0) 4=\left(\frac{36}{11}-Y\right) \times 2$
$(\mathrm{Y}-0) 2=\left(\frac{36}{11}-\mathrm{Y}\right)$
$2 \mathrm{Y}=\frac{36}{11}-\mathrm{Y}$
$\left[Y=\frac{12}{11} \,V\right]$
$\mathrm{V}_{\mathrm{a}}-\mathrm{V}_{\mathrm{b}}=\frac{12}{11} \mathrm{\,V}$
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