Question
Find the principal argument of $\Big(1+\text{i}\sqrt{3}\Big)^2.$

Answer

Let $\text{z}=\Big(1+\text{i}\sqrt{3}\Big)^2$
$=1+3\text{i}^2+2\sqrt{3}\text{i}$
$=1-3+2\sqrt{3}\text{i}$
$=-2+2\sqrt{3}\text{i}$
Let $\beta$ be an acute angle given by $\tan\beta=\Big|\frac{\text{Im(z)}}{\text{Re(z)}}\Big|.$ Then,
$\tan\beta=\Big|\frac{|2\sqrt{3}|}{|2|}\Big|=\big|\sqrt{3}\big|$
$\Rightarrow\tan\beta=\big|\tan\frac{\pi}{3}\big|$
$\Rightarrow\beta=\frac{\pi}{3}$
Clearly, z lies in the second quadrant.
Therefore, the argument of z is given by $\text{arg(z)}=\pi-\frac{\pi}{3}=\frac{2\pi}{3}$
Hence, the principal argument of z is $\frac{2\pi}{3}.$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free