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Trigonometric Functions — Maths STD 11 Science — Question

CBSE BoardEnglish MediumSTD 11 ScienceMathsTrigonometric Functions2 Marks
Question
Find the principal solution of the equation: sin x = $\frac { \sqrt { 3 } } { 2 }$
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Answer

Given, $sin x =$ $\frac { \sqrt { 3 } } { 2 }$
As we know, $sin$ $\frac { \pi } { 3 }$ = $\frac { \sqrt { 3 } } { 2 }$
$\therefore$ $x =$ $\frac { \pi } { 3 }$, which lies in I quadrant.
and $sin$ ($\pi - \frac { \pi } { 3 }$) = $\frac { \sqrt { 3 } } { 2 }$
$\Rightarrow$ $sin$ $\frac { 2 \pi } { 3 }$ = $\frac { \sqrt { 3 } } { 2 }$
$\therefore$ x = $\frac { 2 \pi } { 3 }$, which lies in II quadrant.

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