Question
Find the principal solutions of cosec x = 2

Answer

$\operatorname{cosec} x=2$
$\therefore \operatorname{cosec} x=\operatorname{cosec}\left(\frac{\pi}{6}\right)$ and $\operatorname{cosec} x=\operatorname{cosec}\left(\pi-\frac{\pi}{6}\right)$
$
=\operatorname{cosec}\left(\frac{5 \pi}{6}\right)
$
such that $0 \leq \frac{\pi}{6}<2 \pi$ and $0 \leq \frac{5 \pi}{6}<2 \pi$
$\therefore$ The required principal solutions are $x=\frac{\pi}{6}$ and $x=\frac{5 \pi}{6}$.

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