Gujarat BoardEnglish MediumSTD 12 ScienceMathsInverse Trigonometric Functions1 Mark
Question
Find the principal value of $\cot ^{-1}(\sqrt{3})$.
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Answer
cot-1x represents an angle in (0, $\pi$) whose cotangent is x. Let $x=\cot ^{-1}(\sqrt{3})$ $\Rightarrow \cot x=\sqrt{3}=\cot \left(\frac{\pi}{6}\right)$ $\Rightarrow x=\frac{\pi}{6}$ $\therefore$ Principal value of $\cot ^{-1}(\sqrt{3})$ is $\frac{\pi}{6}$.
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