Question
Find the probability that a leap year selected at random will contain 53 Sundays.

Answer

There are 366 days in a leap year.
Total number of outcomes = 366
Since in a leap year there are 52 weeks,
There will surely be 52 Sundays.
Now, 52 × 7 = 364 days
So, the last two days could be any of the following outcomes:
{(Saturday, Sunday), (Sunday, Monday)}
Thus, P(that there are 53 Sundays)
$=\frac{2}{7}$

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