Question
Find the product: $\frac{6\text{x}}{5}\big(\text{x}^3+\text{y}^3)$
✓
Answer
To find the product, we will use distributive law as follows: $\frac{6\text{x}}{5}\big(\text{x}^3+\text{y}^3)$
$=\frac{6\text{x}}{5}\times \text{x}^3+\frac{6\text{x}}{5}\times \text{y}^3$
$=\frac{6}{5}\times \big(\text{x}\times \text{x}^3)+\frac{6}{5}\times \big(\text{x}\times \text{y}^3\big)$
$=\frac{6}{5}\times \big(\text{x}\times\text{x}^{1+3}\big)+\frac{6}{5}\times \big(\text{x}\times \text{y}^3)$
$=\frac{6\text{x}^4}{5}+\frac{6\text{xy}^3}{5}$
Thus, the answer is $\frac{6\text{x}^4}{5}+\frac{6\text{xy}^3}{5}$
$=\frac{6\text{x}}{5}\times \text{x}^3+\frac{6\text{x}}{5}\times \text{y}^3$
$=\frac{6}{5}\times \big(\text{x}\times \text{x}^3)+\frac{6}{5}\times \big(\text{x}\times \text{y}^3\big)$
$=\frac{6}{5}\times \big(\text{x}\times\text{x}^{1+3}\big)+\frac{6}{5}\times \big(\text{x}\times \text{y}^3)$
$=\frac{6\text{x}^4}{5}+\frac{6\text{xy}^3}{5}$
Thus, the answer is $\frac{6\text{x}^4}{5}+\frac{6\text{xy}^3}{5}$
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