Question
Find the product by $(a)$ cross cancellation method $(b)$ regular method
$11 \frac{2}{3} \times \frac{15}{32}$
$11 \frac{2}{3} \times \frac{15}{32}$
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| + | $5$ | $1$ | $2$ | $6$ | |
| $2$ | $4$ | $6$ | $2$ | ||
| $1$ | $8$ | $3$ | $1$ | ||
| $5$ | $0$ | $1$ |