Question
Find the product $s\left(s^2-s t\right)$ and evaluate it fore $s = 2$ and $t = 3$.

Answer

$s\left(s^2-s t\right)$
$=s \times s^2-s \times s t$
$=s^{(1+2)}-s^{(1+1)} \times t$
$=s^3-s^2 t$
When $s=2$ and $t=3$, we get,
$\text { L.H.S. }=s\left(s^2-s t\right)$
$=2\left(2^2-2 \times 3\right)$
$=2 \times(4-6)$
$=-4$
$\text { R.H.S. }=s^3-s^2 t$
$=2^3-2^2 \times 3$
$=8-12$
$=-4$
$\text { L.H.S. }=\text { R.H.S. }$
$\therefore s\left(s^2-s t\right)=s^3-s^2 t$

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