Question
Find the product:
$ x y\left(x^3-y^3\right) $
$ x y\left(x^3-y^3\right) $
✓
Answer
To find the product, we will use distributive law as follows:
$ x y\left(x^3-y^3\right) $
$ =x y \times x^3-x y \times y^3 $
$ =\left(x \times x^3\right) \times y-x \times\left(y \times y^3\right) $
$ =x^{1+3} y-x y^{1+3} $
$ =x^4 y-x y^4 $
Thus, the answer is $x^4 y-x y^4 $
$ x y\left(x^3-y^3\right) $
$ =x y \times x^3-x y \times y^3 $
$ =\left(x \times x^3\right) \times y-x \times\left(y \times y^3\right) $
$ =x^{1+3} y-x y^{1+3} $
$ =x^4 y-x y^4 $
Thus, the answer is $x^4 y-x y^4 $
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