Question
Find the products: $\Big(\frac{-1}{27}\text{a}^2\text{b}^2\Big)\times \Big(\frac{-9}{2}\text{a}^3\text{bc}^2\Big)$
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Answer
$\Big(\frac{-1}{27}\text{a}^2\text{b}^2\Big)\times \Big(\frac{-9}{2}\text{a}^3\text{bc}^2\Big)$ $=\frac{-1}{27}t\times\Big(\frac{-9}{2}\Big)\text{a}^2\times \text{a}^3\times \text{b}^2\times \text{b}\times \text{c}^2$ $=\frac{1}{3\times 2}\text{a}^{2+3}\times \text{b}^{2+1}\times \text{c}^2$ $=\frac{1}{6}\text{a}^5\text{b}^3\text{c}^2$
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