Find the quotient when difference of 985 and 958 is divided by 9. - Vidyadip

Question

Find the quotient when difference of 985 and 958 is divided by 9.

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Answer

The numbers of three digits are 985 and 958 in which tens and ones digits are reversed, then.
$\overline{\text{abc}}-\overline{\text{acb}}=9(\text{b}-\text{c})$
985 - 958 = 9(8 - 5) = 9 × 3 i. e., it is divisible by 9, then quotient = b - c = 8 - 5 = 3

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